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A persons near point is 50 cm and his far point is 3m. Powers of the lenses he requires for (i) reading and (ii) seeing distant stars are

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–2D and 3D

2D and –3D

2D and 0.33 D

–2D and 0.33 D

answer is B.

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Detailed Solution

$P_{reading} = \frac{100}{f (near point)} = \frac{100}{50} = 2 D$

$P_{distant} = \frac{- 100}{f(far point)} = \frac{100}{3} = 3.33 D$

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