A phonograph turn table rotates at$78\text{\hspace{0.17em}rev/min}$.  Its angular speed in $\text{rad/s}$

Given that a phonograph turn table has frequency

n = 78 rev/min then, $\omega =?$

$\omega =2\pi \text{n}$

$\omega =2\pi \times \frac{78}{60}=8.164\text{rad/s}$

$\therefore \omega =8.164\text{rad/s}$