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Q.

A phosphorus oxide has 43.6% phosphorus. The empirical formula of the compound is ____?

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a

$P_{2} O_{5}$

b

$P_{2} O_{3}$

c

$P_{4} O_{6}$

d

${PO}_{2}$

answer is A.

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Detailed Solution

$\begin{array}{l} P & O \\ 43.6 / 31 = 1.4 & 100 - 43.6 = 56.4 / 16 = 3.52 \\ 1.4 / 1.4 = 1 & 3.52 / 1.4 = 5 / 2 \end{array}$

Simple ratio is 1 : 5/2 = 2.5

Thus the EF is $P_{2} O_{5}$

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