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A photon has energy E which is equal to K.E. of proton. If λ₁ is the wavelength of proton and λ₂ is wavelength of photon then $\frac{{{\lambda _1}}}{{{\lambda _2}}}\$ is directly proportional to

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${E^{1/2}}\$

${E^{ - 1/2}}\$

E²

answer is A.

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Detailed Solution

$\frac{{{\lambda _1}}}{{{\lambda _2}}} = \frac{{h/\sqrt {2ME} }}{{hc/E}}\$

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