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A photon incident on a metal of photo electric work function 2 eV produced photo electron of maximum kinetic energy 2 eV. The wave length associated with the photon is

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6200 $\overset{0}{A}$

3100 $\overset{0}{A}$

9300 $\overset{0}{A}$

2000 $\overset{0}{A}$

answer is B.

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Detailed Solution

$E = W_{0} + K E_{max}$

$∴ \frac{h c}{λ} = W_{o} + K E_{max}$

$∴ \frac{12400}{λ} = 2 + 2$

$∴ λ = 3100^{0} A$

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