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Q.

A photon of 300 nm is absorbed by a gas and then emits two photons. One photon has a wavelength 496 nm then the wavelength of second photon in nm is

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a

959

b

859

c

759

d

659

answer is C.

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Detailed Solution

$\begin{array}{l} E_{absorbed} = E_{emitted} \\ ∴ \frac{hc}{300} = \frac{hc}{496} + \frac{hc}{λ} \\ ∴ λ = 759 nm . \end{array}$

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