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A Photon of light wavelength 6000 Å has energy $E_{1}$ what will be the wavelength of photon of a light which has energy of photon ?

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2000 Å

750 Å

1500 Å

6000 Å

answer is A.

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Detailed Solution

$E = \frac{h c}{λ} o r E α \frac{1}{λ}$

$∴ E_{1} α \frac{1}{6000} a n d E_{2} α \frac{1}{λ_{2}}$

$\begin{array}{l} ∴ \frac{E_{1}}{E_{2}} = \frac{λ_{2}}{6000} \\ ∵ E_{1} = E; E_{2} = 4 E \\ ∴ λ_{2} = 1500 Å \end{array}$

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