A photon of wavelength 4400 $\overset{o}{A}$ is passing through vacuum. The effective mass and momentum of the photon are respectively

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$5 \times 10^{- 36} kg, 1 .67 \times 10^{- 43} kg - m / s$

$5 \times 10^{- 36} kg, 1 .5 \times 10^{- 27} kg - m / s$

$5 \times 10^{- 35} kg, 1 .5 \times 10^{- 26} kg - m / s$

$Zero, 1 .5 \times 10^{- 26} kg - m / s$

answer is A.

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Detailed Solution

$\begin{array}{l} p = \frac{h}{λ} = \frac{6 .6 \times 10^{- 34}}{4400 \times 10^{- 10}} = 1 .5 \times 10^{- 27} kg . m / s \\ and mas s m = \frac{P}{c} = \frac{1 .5 \times 10^{- 27}}{3 \times 10^{8}} = 5 \times 10^{- 36} kg \end{array}$

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