A photon of wavelength is $4 \times 10^{- 7} m$ strikes on a metal surface, the work function of the metal being $3.4 \times 10^{- 19} J$ . Select the correct statements.

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The kinetic energy of the emission is $1.57 \times 10^{- 19} J$

The velocity of photo electron is $5.87 \times 10^{5} {ms}^{- 1}$

The kinetic energy of the emission is 0.98ev

The energy of photon is $4.97 \times 10^{- 19} J$

answer is A, B, C, D.

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Detailed Solution

$\begin{array}{l} E = \frac{hc}{λ} = 4.97 \times 10^{- 19} J K . E = E_{photon} - hv \\ K . E = 4.97 \times 10^{- 19} J - 3.4 \times 10^{- 19} J K . E = 1.57 \times 10^{- 19} J = 0.98 ev (1 J = 6.25 \times 10^{18} ev) \\ v = \sqrt{\frac{2 \times K . E}{m}} = \sqrt{\frac{2 \times 1.57 \times 10^{- 19}}{9.1 \times 10^{- 31}}} = 5.87 \times 10^{5} m / s \end{array}$