A photon was absorbed by a hydrogen atom in its ground state and the electron was promoted to the fifth orbit. When the excited atom returned to its ground state, visible quanta were emitted when electron made transition

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$5 \to 2$

$2 \to 1$

$4 \to 1$

$3 \to 1$

answer is A.

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Detailed Solution

$\begin{array}{l} Visible range \Rightarrow Balmer series i . e ., n_{1} = 2 \\ So, first quanta is from 5 \to 2 (visible quanta) \\ The other quanta will be 2 \to 1 . \end{array}$

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