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A photosensitive material is at 9 m to the left of the origin and the source of light is at 7 m to the right of the origin along x-axis. The photosensitive material and the source of light start from rest and move, respectively, with $8 \hat{i}$ m s^-1 and $4 \hat{i}$ ms^-1. The ratio of intensities at t=0 to t=3 s as received by the photosensitive material is

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2:7

16:1

1:16

7:2

answer is B.

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Detailed Solution

The separation between source and photosensitive material at t:0 is 16 m. Therefore, intensity received by photosensitive material at t=0 is $I_{0} = P / (4 π \times 16^{2})$ ,where P is the power of source of light.

At t: 3 s, the source is at (15, 0) and detector is at (19, 0), so the separation between them is 4 m.

$\begin{array}{l} I_{2} = \frac{P}{4 π \times 4^{2}} \\ So, \frac{I_{1}}{I_{2}} = \frac{1}{16} \end{array}$

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