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A photosensitive material is at 9 m to the left of the origin and the source of light is at 7 m to the right of the origin along x - axis. The photosensitive material and the source of light start from rest and moves, respectively, with $8 \hat{i} {ms}^{- 1}$ and $4 \hat{i} {ms}^{- 1}$ . The ratio of intensities at t = 0 to t = 3 s as received by the photosensitive material is

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16 : 1

1 : 16

2 : 7

7 : 2

answer is B.

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Detailed Solution

$I_{1} = \frac{P}{4 π (16)^{2}}; I_{2} = \frac{P}{4 π (4)^{2}}$

$∴ \frac{I_{1}}{I_{2}} = \frac{1}{16}$

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