Q.

A physical parameter can be determined by measuring the parameters b, c, d and e using the relation a=bαcβ/dγeδ If the maximum errors in the measurement of  b, c, d and e are b1%,c1%,d1%and  e1%then the maximum error in the value of  a determined by the experiment is

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a

(b1+c1+d1+e1)%

b

(b1+c1 d1 e1 )%

c

(αb1+βc1γd1δe1)%

d

(αb1+βc1+γd1+δe1)%

answer is D.

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Detailed Solution

a=bαcβ/dγeδ

So maximum error in  is given by

Δaa×100max

=α.Δbb×100+β.Δcc×100+γ.Δdd×100+δ.Δee×100

=(αb1+βc1+γd1+δe1)%

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