A physical quantity 'Q' is related to four observables x, y, z and 't' by the relation Q=x2/5z3yt.The percentage errors of measurements in x, y, z and 't' are 2.5%, 2%, 0.5% and 1% respectively. The percentage error in Q will be

ΔQQ×100=25Δxx×100+3Δzz×100+Δyy×100+12Δtt×10025×(2.5)+3(0.5)+(2)+12(1)=1+1.5+2+0.5=5%

A physical quantity 'Q' is related to four observables x, y, z and 't' by the relation Q=x2/5z3yt.The percentage errors of measurements in x, y, z and 't' are 2.5%, 2%, 0.5% and 1% respectively. The percentage error in Q will be

ΔQQ×100=25Δxx×100+3Δzz×100+Δyy×100+12Δtt×10025×(2.5)+3(0.5)+(2)+12(1)=1+1.5+2+0.5=5%

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

A physical quantity 'Q' is related to four observables x, y, z and 't' by the relation $Q = \frac{x^{2 / 5} z^{3}}{y \sqrt{t}}$ .The percentage errors of measurements in x, y, z and 't' are 2.5%, 2%, 0.5% and 1% respectively. The percentage error in Q will be

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

5%`

4.5%

7.75%

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$\begin{array}{l} \frac{ΔQ}{Q} \times 100 = \frac{2}{5} \frac{Δx}{x} \times 100 + 3 \\ \frac{Δz}{z} \times 100 + \frac{Δy}{y} \times 100 + \frac{1}{2} \frac{Δt}{t} \times 100 \\ \frac{2}{5} \times (2 .5) + 3 (0 .5) + (2) + \frac{1}{2} (1) \\ = 1 + 1 .5 + 2 + 0 .5 = 5 % \end{array}$