Q.

A physical quantity Q is related to four observables a, b, c, d as follows : Q=ab4cdwhere,a=(60±3)Pa;b=(20±0.1)m; c=(40±0.2)Nsm2andd=(50±0.1)m, then the percentage error in Q is x1000 where x = ______.

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answer is 7700.

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Detailed Solution

 Q=ab4cd ΔQQ×100=[Δaa+4Δbb+Δcc+Δdd]×100 x1000=[360+4(0.120)+(0.240)+0.150]×100 x=7700

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