A piece of ice floating in a beaker containing thick sugar solution of water. As the ice melts, 

the total level of the liquid

Let $\mathrm{\rho }=$ density of sugar solution $>{\mathrm{\rho }}_{\mathrm{w}}$

and m= mass of ice

In floating condition weight = upthrust

$$\begin{gathered} \therefore \mathrm{mg}={\mathrm{V}}_{\mathrm{D}}\mathrm{\rho g} \\ \mathrm{or} \\ {\mathrm{V}}_{\mathrm{D}}=\frac{\mathrm{m}}{\mathrm{\rho }} \end{gathered}$$

When ice melts, m mass of ice becomes m mass of water. Volume of this water formed.

${\mathrm{V}}_{\mathrm{F}}=\frac{\mathrm{m}}{{\mathrm{\rho }}_{\mathrm{w}}}$

Since, ${\mathrm{\rho }}_{\mathrm{w}}<\mathrm{\rho },{\mathrm{V}}_{\mathrm{F}}>{\mathrm{V}}_{\mathrm{D}}$. Hence, level will increase.