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Q.

A piece of ice (specific heat capacity of ice= 2100 J kg-1 °C-1 and latent heat of ice = 3.36X105 J kg-1 ) of mass "m" grams is at -5°C at atmospheric pressure. It is given 420 J of heat so that the ice starts melting. Finally, when the ice-water mixture is in equilibrium, it is found that 1 gm of ice has melted. The value of m is

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answer is 8.

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Detailed Solution

Q=msΔθ+mL420=m×10−3×2100×5+10−3×3.36×105

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