Q.

A piece of iron of density 7800 kg/m3 and volume 100cm3  is completely immersed in water. Calculate the apparent weight of an iron piece in water.


[Take, g=10m/s2 ]   


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a

6.8N

b

1N

c

7.8N

d

8.8 N 

answer is A.

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Detailed Solution

Concept:  When a body is immersed in a liquid, the liquid exerts a force of buoyancy on the body in the upward direction. Find the buoyancy force and the gravitational force on the iron piece by using the formulas Question Image Mostly the earth exerts a force called gravitational force Fg on a body within its gravity that is very attractive in nature.
When a body is put in water or any other liquid, the liquid exerts a force on the substance. This force is called up thrust or buoyancy force (FB). The direction of this force is always in the upward direction i.e. in the opposite direction of the gravitational force.
Question Image Here, ρ is the density of the liquid in which the body is immersed; V is the volume of the body that is submerged in the liquid.
the net force on the body is
Question Image Question Image Mass=density×volume
Given the density of the body is given as 7800Question ImageVolume is 100Question Image Question Image Fg=mg
   =Question ImageTo calculate the buoyancy force Question ImageQuestion ImageQuestion Image07.8−1=6.8N
Hence, Apparent weight of Iron piece in water is 6.8N
Hence, option 1 is correct.
 
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