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Q.

 A piece of lead falls from a height of 100m on a fixed non-conducting slab which brings it to rest. If the specific heat of lead is 30.6 cal/kg °C, the increase in temperature of the slab immediately after collision

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a

6.72°C

b

8.72°C

c

5.62°C

d

7.62°C

answer is B.

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Detailed Solution

h=100m; s=30.6cal/kg0C mgh =J.msΔθ⇒Δθ=ghJs=9.8×1004.2×30.6=980128.52 =7.625∘C

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