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Q.

A piece of metal floats on mercury. The coefficients of volume expansion of the metal and mercury are  γ1 and  γ2  respectively. If the temperature of both mercury and metal are increase by an amount  ΔT  the fraction the volume of the metal submerged in mercury changes by the factor.

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a

1(γ2γ1)ΔT

b

1(γ1γ2)ΔT

c

(γ1γ2)ΔT

d

(γ2γ1)ΔT

answer is D.

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Detailed Solution

Let density of the metal and mercury be d1 and d2 respectively.

The fraction of volume of metal submerged initially, f=d1/d2

Density of metal after increase of temperature by Δt, d1'=d11+γ1ΔT

Density of mercury after increase of temperature by Δt, d2'=d21+γ2ΔT

So, fraction of volume of metal submerged finally, f'=d1'd2'=d1(1+γ2ΔT)d2(1+γ1ΔT)=d1(γ2-γ1)ΔTd2

f'=f(γ2-γ1)ΔT

f'f=(γ2-γ1)ΔT

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