Q.

A piece of plumber's solder weighing 3.0gm was dissolved in dilute nitric acid, then treated with dilute H2SO4. This precipitated the lead as PbSO4, which after washing and drying weighed 2.93gm.The solution was then neutralized to precipitate stannic acid, which was decomposed by heating, yielding 1.27gm SnO2. What is the analysis of the solder? Pb=207.2amu,Sn=118.7amu).

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a

66.7% Pb,33.3%Sn 

b

33.3% Pb,66.7%Sn

c

1gmPb,2gmSn

d

2gmPb,1gmSn

answer is A, D.

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Detailed Solution

Percentage of lead

%Pb=2.93303.2×13×100×207.2=66.7%; %Sn=33.3%=2g =1g

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