A piston of cross-sectional area 100 cm2 is used in a hydraulic pressure to exert a force of 107 dyne on the water. The cross-sectional area of the other piston which supports an object having a mass of 2000 kg is

∵F1A1=F2A2 (Pascal's law)⇒ Cross-sectional area of the other piston,A2=F2F1⋅A1=2000×9.8×105107(100)=1.96×104cm2

A piston of cross-sectional area 100 cm2 is used in a hydraulic pressure to exert a force of 107 dyne on the water. The cross-sectional area of the other piston which supports an object having a mass of 2000 kg is

∵F1A1=F2A2 (Pascal's law)⇒ Cross-sectional area of the other piston,A2=F2F1⋅A1=2000×9.8×105107(100)=1.96×104cm2

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A piston of cross-sectional area 100 cm² is used in a hydraulic pressure to exert a force of 10⁷ dyne on the water. The cross-sectional area of the other piston which supports an object having a mass of 2000 kg is

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9.8 x 10² cm²

9.8 x 10³ cm²

1.96 x 10³ cm²

1.96 x 10⁴ cm²

answer is A.

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$∵ \frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}}$ (Pascal's law)

$\Rightarrow$ Cross-sectional area of the other piston,

$A_{2} = \frac{F_{2}}{F_{1}} \cdot A_{1} = (\frac{2000 \times 9.8 \times 10^{5}}{10^{7}}) (100) = 1.96 \times 10^{4} {cm}^{2}$

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A piston of cross-sectional area 100 cm2 is used in a hydraulic pressure to exert a force of 107 dyne on the water. The cross-sectional area of the other piston which supports an object having a mass of 2000 kg is

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A piston of cross-sectional area 100 cm² is used in a hydraulic pressure to exert a force of 10⁷ dyne on the water. The cross-sectional area of the other piston which supports an object having a mass of 2000 kg is