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A piston of cross sectional area $10 c m^{2}$ is used in a hydraulic press to exert a force of $10^{7}$ dyne on water. The cross sectional area of the other piston which supports a truck of mass 200kg is ______ $c m^{2} (g = 10 m / s^{2})$

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answer is 200.

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Detailed Solution

$\frac{F_{1}}{A_{1}} = \frac{F_{2}}{A_{2}} \Rightarrow \frac{10^{7}}{10} = \frac{200 \times 10^{3} \times 10^{3}}{A_{2}} \Rightarrow A_{2} = \frac{2 \times 10^{8}}{10^{6}} \Rightarrow A_{2} = 2 \times 10^{2} c m^{2} = 200 c m^{2}$

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