A plane electromagnetic wave, has frequency of 2.0×1010 Hz and its average energy density is 1.02×10−8J/m3 in vacuum. The amplitude of the magnetic field of the wave is close to (14πε0=9×109Nm2C2 and speed of light =3×108ms−1)

f=2×1010 hz; energy density = 1.02×10−8 J/m312ε0E2=1.02×10−8 or E2=1.02×2×10−8ε0, B=Ec=483×108=16×10−8⇒B=160 nT

A plane electromagnetic wave, has frequency of 2.0×1010 Hz and its average energy density is 1.02×10−8J/m3 in vacuum. The amplitude of the magnetic field of the wave is close to (14πε0=9×109Nm2C2 and speed of light =3×108ms−1)

f=2×1010 hz; energy density = 1.02×10−8 J/m312ε0E2=1.02×10−8 or E2=1.02×2×10−8ε0, B=Ec=483×108=16×10−8⇒B=160 nT

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A plane electromagnetic wave, has frequency of $2.0 \times 10^{10} H z$ and its average energy density is $1.02 \times 10^{- 8} J / m^{3}$ in vacuum. The amplitude of the magnetic field of the wave is close to $(\frac{1}{4 π ε_{0}} = 9 \times 10^{9} \frac{N m^{2}}{C^{2}} a n d s p e e d o f l i g h t = 3 \times 10^{8} m s^{- 1})$

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150 Nt

160 nT

180 nT

190 nT

answer is B.

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Detailed Solution

$f = 2 \times 10^{10} h z;$ energy density = $1.02 \times 10^{- 8} J / m^{3}$

$\frac{1}{2} ε_{0} E^{2} = 1.02 \times 10^{- 8} o r E^{2} = \frac{1.02 \times 2 \times 10^{- 8}}{ε_{0}}, B = \frac{E}{c} = \frac{48}{3 \times 10^{8}} = 16 \times 10^{- 8} \Rightarrow B = 160 n T$

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