A plane electromagnetic wave of frequency 500 MHz is travelling in vacuum along y – direction. At a particular point in space and time, B→=8.0×10−8z^T . The value of electric field at this point is:(Speed of light =3×108ms−1)x^, y^, z^ are unit vectors along x, y and z directions.

C=EB⇒E=CB=3×108×8×10−8=24V/m Direction of (B^×C^) is direction of E^ , ⇒E^=(B^×C^)=z^×y^=−x^

A plane electromagnetic wave of frequency 500 MHz is travelling in vacuum along y – direction. At a particular point in space and time, B→=8.0×10−8z^T . The value of electric field at this point is:(Speed of light =3×108ms−1)x^, y^, z^ are unit vectors along x, y and z directions.

C=EB⇒E=CB=3×108×8×10−8=24V/m Direction of (B^×C^) is direction of E^ , ⇒E^=(B^×C^)=z^×y^=−x^

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A plane electromagnetic wave of frequency 500 MHz is travelling in vacuum along y – direction. At a particular point in space and time, $\vec{B} = 8.0 \times 10^{- 8} \hat{z} T$ . The value of electric field at this point is:
(Speed of light $= 3 \times 10^{8} m s^{- 1}$ )
$\hat{x}, \hat{y}, \hat{z}$ are unit vectors along x, y and z directions.

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$- 24 \hat{x} V / m$

$2.6 \hat{x} V / m$

$- 2.6 \hat{x} V / m$

$24 \hat{x} V / m$

answer is A.

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Detailed Solution

$\begin{array}{l} C = \frac{E}{B} \\ \Rightarrow E = CB = 3 \times 10^{8} \times 8 \times 10^{- 8} = 24 V / m \\ Direction of (\hat{B} \times \hat{C}) is direction of \hat{E}, \\ \Rightarrow \hat{E} = (\hat{B} \times \hat{C}) = \hat{z} \times \hat{y} = - \hat{x} \end{array}$