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A plane electromagnetic wave of frequency 30 MHz travels in free space along the positive X direction, at a particular point in space and time $\vec{E} = 5 \hat{k} {Vm}^{- 1} .$ Then, value of $\bar{B}$ at that point

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$1.67 \times 10^{- 8} T (\hat{- j})$

$1.67 \times 10^{- 8} T (i)$

Zero

$\infty$

answer is A.

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Detailed Solution

$B = \frac{E}{C} = \frac{5}{3 \times 10^{8}} = 1.67 \times 10^{- 8} V / m$

$\vec{E} \times \overset{⇀}{B} = \overset{⇀}{C} \hat{k} \times \overset{⇀}{B} = \hat{i} \hat{k} \times - \hat{j} = \hat{i}$

$Here \vec{B} = should be [- \hat{j}]$

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