A plane electromagnetic wave of wave intensity 6 W/m2 strikes a small mirror area 40 cm2, held perpendicular to the approaching wave. The momentum transferred by the wave to the mirror each second will be

6 .4 × 10 − 7 kg − m / s 2

6 .4 × 10 − 7 kg − m / s 2

1.6 × 10 − 10 kg − m / s 2

6 .4 × 10 − 7 kg − m / s 2

Book Online Demo

Check Your IQ

Try Test

Courses

Offline Centres

A plane electromagnetic wave of wave intensity 6 W/m² strikes a small mirror area 40 cm², held perpendicular to the approaching wave. The momentum transferred by the wave to the mirror each second will be

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

$3.2 \times 10^{- 9} kg - m / s^{2}$

$1.6 \times 10^{- 10} kg - m / s^{2}$

$4.8 \times 10^{- 8} kg - m / s^{2}$

$6 .4 \times 10^{- 7} kg - m / s^{2}$

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Momentum transferred in one second

$P = \frac{2 U}{c} = \frac{2 S_{av} A}{c} = \frac{2 \times 6 \times 40 \times 10^{- 4}}{3 \times 10^{8}}$

$= 1.6 \times 10^{- 10} kg - m / s^{2}$

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE