Q.

A plane electromagnetic wave travels in a medium of relative permeability 1.61 and relative permittivity 6.44. If magnitude of magnetic intensity is 4.5×10-2Am-1 at a point, what will be the approximate magnitude of electric field intensity at that point ?
(Given : permeability of free space μ0=4π×10-7 NA-2, speed of light in vacuum c =3×108 ms-1 )

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a

2.25×10-2Vm-1

b

16.96Vm-1

c

8.48Vm-1

d

6.75×106Vm-1

answer is C.

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Detailed Solution

 μr=1.61 ϵr=6.44 B=4.5×102 E=? C=1μ0ϵ0V=1μ CV=μrϵr=1.61×6.44 EB=V=3×1081.61×6.44=9.32×107m/s E=4.5×102×9.32×107 =4.2×106

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