A plane em wave of wave intensity of 10 W/m2 strikes a small mirror of area 20 cm2, held perpendicular to the approaching wave. The radiation force on the mirror will be

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A plane em wave of wave intensity of 10 W/m² strikes a small mirror of area 20 cm², held perpendicular to the approaching wave. The radiation force on the mirror will be

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$1.33 \times 10^{- 11} N$

$1.33 \times 10^{- 10} N$

$6.6 \times 10^{- 10} N$

$6.6 \times 10^{- 11} N$

answer is C.

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Detailed Solution

Radiation force = Momentum transferred per second by electromagnetic wave to the mirror

$= \frac{2 I_{a v} A}{c} = \frac{2 \times (10) \times (20 \times 10^{- 4})}{(3 \times 10^{8})} = 1.33 \times 10^{- 10} N$

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