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Q.

A plane is inclined at an angle α=300 with respect to the horizontal.  A particle is projected with a speed u=2ms1, from the base of the plane, as shown in figure.  The distance from the base, at which the particle hits plane is close to : takeg=10ms2

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a

20cm   

b

18 cm 

c

14 cm

d

26 cm 

answer is A.

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Detailed Solution

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On an inclined plane, time of flight (t) is given by 

T=2usinθgcosα

T=22sin150gcos300

T=4sin15010cos300

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S=2cos154sin1510cos3012×10sin3016sin215100cos230S=1631660S=0.1952mS=0.20mS=20.0cm

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