Q.

A plane makes intercepts OA, OB and OC whose measurements are D and c on the OX, OY and OZ axes. The area of triangle ABC is

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a

12(ab+bc+ca)

b

12abc(a+b+c)

c

12a2b2+b2c2+c2a21/2

d

12(a+b+c)2

answer is C.

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Detailed Solution

 Plane meets axes at A(a, 0, 0), B(0, b, 0) and C(0, 0, c). 

Then area of ABC

=12|AB×AC|=12|(ai^+bj^)×(ai^+ck^)|=12a2b2+b2c2+c2a2

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