Q.

A plane mirror is lying in xy plane. Object velocity is v0=(2i^-3j^+4k^) m/s. Find the image velocity.

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a

(2i^+3j^+4k^) m/s

b

(2i^-3j^+4k^) m/s

c

(2i^-3j^-4k^) m/s

d

(2i^+3j^-4k^) m/s

answer is B.

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Detailed Solution

Components of object velocity parallel to plane mirror (or lying in xy plane) remain unchanged. But, component perpendicular to plane mirror changes its direction but magnitude remains the same.

hence, the image velocity is vI = (2i^-3j^-4k^) m/s 

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