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A plane polarized beam of intensity I is incident on a polariser with the electric vector inclined at $30^{0}$ to the optic axis of the polariser passes through an analyzer whose optic axis is inclined at $30^{0}$ to that of polariser. Intensity of light coming out of the analyzer is

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(3/4)I

(9/16)I

$\frac{\sqrt{3}}{2} I$

(1/4)I

answer is A.

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Detailed Solution

after polariser intensity $I \cos^{2} 30^{0}$ after analyzer it becomes $I \cos^{2} 30^{0} \cos^{2} 30^{0}$

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