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A plane progressive wave of frequency 25 Hz amplitude 2.5 × 10^-5 m and initial phase zero propagates along negative x-direction with a velocity of 300 m/s. At any instant, the phase difference between the oscillations at two points 6 m apart along the line is π and the corresponding amplitude difference is A.

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A=0

A=2.5 × 10^-5m

π=0

$ϕ = π$

answer is A, D.

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Detailed Solution

$λ = \frac{V}{f} = \frac{300}{25} = 12 m$
Amplitude difference, A = 0
Phase diff $= π = ϕ$

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