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A plane progressive wave of frequency 25Hz, amplitude $2.5 \times 10^{- 5} m$ and initial phase zero propagates along negative x-direction with a velocity of 300 m/s. At any instant, the phase difference between the oscillations at two points 6m apart along the line of propagation is $ϕ$ and the corresponding amplitude difference is A.

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$A = 2.5 \times 10^{- 5} m$

A=0

$ϕ = π$

$ϕ = 0$

answer is A, D.

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Detailed Solution

$λ = \frac{V}{f} = \frac{300}{25} = 12 m$

Amplitude difference

A=zero

Phase diff $= π = ϕ$

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