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A planet having mass 9 M_e and radius 4R_e, where M_eand R_eare mass and radius of earth respectively, has escape velocity in km/s given by:
(Given escape velocity on earth $V_{e} = 11.2 \times 10^{3}$ m/s)

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16.8

33.6

11.2

67.2

answer is B.

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Detailed Solution

$V_{e s c a p e} = \sqrt{\frac{2 GM}{R}} \propto \sqrt{\frac{M}{R}}$

$\frac{V_{P}}{V_{e}} = \sqrt{\frac{M_{P} / M_{e}}{R_{p} / R_{a}}} = \sqrt{\frac{9}{4}} = \frac{3}{2} V_{P}$

$V_{P} = \frac{3}{2} \times 11.2 = 16.8 km / \sec$

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