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Q.

A planet is observed by an astronomical refracting telescope having an objective of focal length 16 m and an eye-piece of focal length 2 cm.

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a

The distance between the objective and the eye-piece is 16.02 m

b

The angular magnification of the planet is 800

c

The image of the planet is inverted

d

The objective is larger than the eye-piece

answer is A, B, C, D.

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Detailed Solution

Magnification, M=−f0fc=−16002=−800
L = f0 +  fe = 16 + 0.02 = 16.02m

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