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Q.

A plano-convex lens is made of material of refractive index 1.6. The radius of curvature of the curved surface is 60 cm. What is the focal length of the lens?

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Detailed Solution

$R_{1} = 60 cm, R_{2} = α, μ = 1.6 \frac{1}{f} = (μ - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}}) \frac{1}{f} = (1.6 - 1) (\frac{1}{60}) \Rightarrow f = 100 cm .$

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