A plant virus is found to consists of uniform cylindrical particles of $150 A^{0}$ in diameter & $5000 A^{0}$ long. The specific volume of the virus is $0. {75cm}^{3} / g .$ If the virus is considered to be a single particle, its molecular weight is $x \times 10^{7} .$ Then $x$ is (Round off to nearest integer)

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answer is 7.

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Detailed Solution

$Percentage loss in mass = 2 \times \frac{18}{266.5} \times 100 = 13.50 % Specific volume = \frac{Volume}{Mass} Mass = \frac{{πr}^{2} h}{Specificvolume} = \frac{3.14 \times {(75 \times 10^{- 8})}^{2} \times 5000 \times {10^{- 8}}^{}}{0.75} Molar mass = Mass \times N = 3.14 \times {(75 \times {10^{- 8}}^{})}^{2} \times 5000 \times 10^{- 8}$