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A plastic ball falling from a height 4.9 m rebounds number of times. If total time for second collision is 2.4s, then e =

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0.6

0.3

0.7

0.4

answer is C.

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Detailed Solution

$T = t_{0} + 2 t_{1} = \sqrt{\frac{2 h}{g}} [1 + 2 e] since t_{n} = e^{n} t$

On putting the values,

$2.4 = \sqrt{\frac{2 \times 4.9}{9.8}} (1 + 2 e) \Rightarrow e = 0.7$

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