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Q.

A player caught a cricket ball of mass 150g moving at a rate of 20 m/s. If the catching process is completed in 0.1s, the force (in N ) of the blow exerted by the ball on the hand of the player is equal to

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answer is 30.

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Detailed Solution

Change in momentum =Impulse $= | 0.15 kg \times 0 - 0.15 kg \times 20 m / s | = 3 kg m / s$

$F_{Av} = \frac{ΔP}{Δt} = \frac{3 kgm / s}{0.1 s} = 30 N$

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