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A player caught a cricket ball of mass $150 g$ moving at a rate of $20 m / s$ . If the catching process is completed in $0.1 s$ , the force ball exerted by the ball on the hand of the player is equal to –

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$30 N$

$3 N$

$300 N$

$150 N$

answer is A.

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Detailed Solution

$F = \frac{0.150 \times 2}{0.1} = 30 N$

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