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A player stops a football weighing 0.5 kg which comes flying towards him with a velocity of 10m/s. If the impact lasts for 1/50th sec. and the ball bounces back with a velocity of 15 m/s, then the average force involved is

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250 N

1250 N

500 N

625 N

answer is D.

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Detailed Solution

Here $m = 0.5 kg; u = - 10 m / s;$
$t = 1 / 50 s; v = + 15 {ms}^{- 1}$
Force $= m (v - u) / t = 0.5 (10 + 15) \times 50 = 625 N$

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