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A point change q is placed inside a cone as shown in figure. Electric flux passing through the curved surface of the cone is

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$\frac{q}{2 \in_{0}}$

$\frac{q}{4 \in_{0}}$

$\frac{3 q}{4 \in_{0}}$

$\frac{2 q}{3 \in_{0}}$

answer is C.

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Detailed Solution

$ϕ$ Curved surface = $\frac{q}{ε_{0}} - \frac{q}{2 ε_{0}} (1 - \cos α)$

$= \frac{3 q}{4 ε_{0}}$

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