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A point charge $4 \times 10^{- 2} C$ is moved from P to S in a uniform electric field of 60 N/C directed along positive x-axis. If coordinates of P and S are (2, 3, 0) and (1, 1, 1) m respectively, the work done by electric field will be

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$- 600 m J$

$600 m J$

$- 2400 m J$

$2400 m J$

answer is C.

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Detailed Solution

$W = \bar{F} . \bar{S} \bar{F} = \bar{E} q = 60 \times 4 \times 10^{- 2} \bar{i} \bar{S} = (\bar{i} + \bar{j} + \bar{k}) - (2 \bar{i} + 3 \bar{j} + 0 \bar{k})$

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