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A point charge is placed on the axis of an electric dipole at a distance r from its centre. Magnitude of force experienced by the charge is F. Now the dipole is rotated through an angle of 45°, then the magnitude of force experienced by the dipole will be

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$\sqrt{\frac{5}{8}} F$

$\sqrt{\frac{3}{8}} F$

$\sqrt{\frac{7}{8}} F$

$\sqrt{\frac{3}{2}} F$

answer is A.

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Detailed Solution

Initially, $F = E . Q = \frac{1}{4 π \in_{o}} \frac{2 p}{r^{3}} Q$

Finally, $F' = E' . Q = \frac{1}{4 π \in_{o}} . \frac{p}{r^{3}} \sqrt{3 \cos^{2} 45^{o} + 1} Q = \sqrt{\frac{5}{8}} F$

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