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A point charge of 40 stat coulomb is placed 2 cm in front of an earthed metallic plane plate of large size. Then the force of attraction on the point charge is

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100 dynes

160 dynes

1600 dynes

400 dynes

answer is A.

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Detailed Solution

By the concept of electrical image, it is considered that an equal but opposite charge present on the other side of the plate at equal distance. Hence force
$F = \frac{{40 \times 40}}{{{4^2}}} = 100\,dynes$

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