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A point charge of $+ 6 μ c$ is placed at a distance 20cm directly above the centre of a square of side 40cm. The magnitude of the flux through the square is

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$ε_{0}$

$\frac{1}{ε_{0}}$

$ε_{0} \times 10^{- 6}$

$\frac{1}{ε_{0}} \times 10^{- 6}$

answer is D.

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Detailed Solution

$ϕ = \frac{q}{6 \in_{0}} = \frac{6 \times 10^{- 6}}{6 \times \in_{0}} = \frac{1}{\in_{0}} \times 10^{- 6}$

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