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A point charge q is placed at a distance r from the centre of an uncharged conducting sphere of radius R(< r). The potential at any point on the sphere is :

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$\frac{1}{4 π \in_{0}} \frac{q}{r}$

$\frac{1}{4 π \in_{0}} \frac{{qr}^{2}}{R}$

$\frac{1}{4 π \in_{0}} \frac{qR}{r^{2}}$

Zero

answer is B.

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Detailed Solution

Potential due to negative and positive induced charges is zero so $V = \frac{1}{4 {πε}_{0}} \frac{q}{r}$

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