A point charge +Q is placed at the centroid of an equilateral triangle. When a second charge +Q is placed at a vertex of the triangle, the magnitude of the electrostatic force on the central charge is 0.1N. the magnitude of the net force on the central charge when a third charge +Q is placed at another vertex of the triangle is

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0.1N

0.2N

Zero

0.12N

answer is D.

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Detailed Solution

The centroid will be at equal distance from both of the vertices, so two forces of same magnitude at $120 ∘$ angle act on the charge at centroid.

$F_{R} = \sqrt{F^{2} + F^{2} + 2 F . Fcos 120} = F = 0.1 N$

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